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0.21x^2-6x+20=0
a = 0.21; b = -6; c = +20;
Δ = b2-4ac
Δ = -62-4·0.21·20
Δ = 19.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{19.2}}{2*0.21}=\frac{6-\sqrt{19.2}}{0.42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{19.2}}{2*0.21}=\frac{6+\sqrt{19.2}}{0.42} $
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